Quadratic Equation is nothing but a equation in terms of **ax ^{2}+bx+c = 0** (where a, b and c are coefficients). The roots of the above equation is

The term `b`

is referred as the discriminant of a quadratic equation. The discriminant tells the nature of the roots.^{2}-4ac

- If discriminant is greater than 0, the roots are real and different.
- If discriminant is equal to 0, the roots are real and equal.
- If discriminant is less than 0, the roots are complex and different.

**Table of Contents**

## Find the Roots of a Quadratic Equation in C++

```
#include <iostream>
#include <cmath>
using namespace std;
int main() {
float a, b, c, x1, x2, discriminant, realPart, imaginaryPart;
cout << "Enter coefficients a, b and c: ";
cin >> a >> b >> c;
discriminant = b*b - 4*a*c;
if (discriminant > 0) {
x1 = (-b + sqrt(discriminant)) / (2*a);
x2 = (-b - sqrt(discriminant)) / (2*a);
cout << "Roots are real and different." << endl;
cout << "x1 = " << x1 << endl;
cout << "x2 = " << x2 << endl;
}
else if (discriminant == 0) {
cout << "Roots are real and same." << endl;
x1 = -b/(2*a);
cout << "x1 = x2 =" << x1 << endl;
}
else {
realPart = -b/(2*a);
imaginaryPart =sqrt(-discriminant)/(2*a);
cout << "Roots are complex and different." << endl;
cout << "x1 = " << realPart << "+" << imaginaryPart << "i" << endl;
cout << "x2 = " << realPart << "-" << imaginaryPart << "i" << endl;
}
return 0;
}
```

If.. else condition iterates to find the roots of a quadratic equation. The real and imaginary parts are calculated using realPart = -b/(2*a); , imaginaryPart =sqrt(-discriminant)/(2*a); functions. If you enter the coefficients then the program displays the roots of the quadratic equation.

Read Also : Floyd's Triangle in C++

## Output

```
Enter coefficients a, b and c: 4
5
1
Roots are real and different.
x1 = -0.25
x2 = -1
```

## Final Words

I hope this article helps you to Find the Roots of a Quadratic Equation in C++ Program. If you face any issues please let me know via the comment section. Share this article with other C++ program developers via social networks.