Contents

## Java program to print spiral pattern of the given input

``````import java.util.Scanner;

public class Pattern22
{
public static void main(String args[])
{
// create object.
Scanner sc = new Scanner(System.in);

// enter the number of elements.
System.out.print("Enter the number of elements for pattern : ");
int n = sc.nextInt();

int A[][] = new int[n][n];
int k=1, c1=0, c2=n-1, r1=0, r2=n-1;

while(k<=n*n)
{
for(int i=c1;i<=c2;i++)
{
A[r1][i]=k++;
}

for(int j=r1+1;j<=r2;j++)
{
A[j][c2]=k++;
}

for(int i=c2-1;i>=c1;i--)
{
A[r2][i]=k++;
}

for(int j=r2-1;j>=r1+1;j--)
{
A[j][c1]=k++;
}

c1++;
c2--;
r1++;
r2--;
}

/* Printing the Spiral pattern */
System.out.println("The Spiral pattern is : ");
for(int i=0;i<n;i++)
{
for(int j=0;j<n;j++)
{
System.out.print(A[i][j]+ "\t");
}
System.out.println();
}
}
}
``````

## Output

``````First run:
Enter the number of elements for pattern : 5
The Spiral pattern is :
1	2	3	4	5
16	17	18	19	6
15	24	25	20	7
14	23	22	21	8
13	12	11	10	9

Second run:
Enter the number of elements for pattern : 10
The Spiral pattern is :
1	2	3	4	5	6	7	8	9	10
36	37	38	39	40	41	42	43	44	11
35	64	65	66	67	68	69	70	45	12
34	63	84	85	86	87	88	71	46	13
33	62	83	96	97	98	89	72	47	14
32	61	82	95	100	99	90	73	48	15
31	60	81	94	93	92	91	74	49	16
30	59	80	79	78	77	76	75	50	17
29	58	57	56	55	54	53	52	51	18
28	27	26	25	24	23	22	21	20	19
``````

### Ranjith

Hi, I'm Manoj a full-time Blogger, YouTuber, Affiliate Marketer, & founder of Coding Diksha. Here, I post about programming to help developers.